What is the d/(dt)((x)(8t)) ?

The d/(dt)((x)(8t)) is 8(t(dx)/(dt)+x)

What is the first d/(dt)((x)(8t)) ?

The first d/(dt)((x)(8t)) is 8(t(dx)/(dt)+x)

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\frac{d}{d t} ((x) (8 t))

8 (t \frac{d x}{d t} + x)

Solution steps

\frac{d}{d t} ((x) (8 t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d t} (x t)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = t

= 8 (\frac{d x}{d t} t + \frac{d t}{d t} x)

\frac{d t}{d t} = 1

= 8 (\frac{d x}{d t} t + 1 \cdot x)

Simplify

= 8 (t \frac{d x}{d t} + x)

f (2) \frac{d}{d x} (x^{3} + 1)

(sec (x))^{2} - 2 tan (x)

\frac{d}{d x} ((f (x)) (ln (x y)))

3 (pq)

x 2 - 7 x + 18

What is the d/(dt)((x)(8t)) ?
The d/(dt)((x)(8t)) is 8(t(dx)/(dt)+x)
What is the first d/(dt)((x)(8t)) ?
The first d/(dt)((x)(8t)) is 8(t(dx)/(dt)+x)