What are the solutions to the equation 3(x-1)^2-14=-2 ?

The solutions to the equation 3(x-1)^2-14=-2 are x=3,x=-1

Find the zeros of 3(x-1)^2-14=-2

The zeros of 3(x-1)^2-14=-2 are x=3,x=-1

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3 (x - 1)^{2} - 14 = - 2

x = 3, x = - 1

Solution steps

3 (x - 1)^{2} - 14 = - 2

Move

14

to the right side

3 (x - 1)^{2} = 12

Divide both sides by

3

(x - 1)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 4 : x = 3

Solve

x - 1 = - 4 : x = - 1

The solutions to the quadratic equation are:

x = 3, x = - 1

(7 + 8) (7 - 8)

14 \cdot \frac{3}{2}

- 3 x^{2} + 1 = (x - 2) (x + 2)

x^{3} + 4 x

48 t - 16 t^{2} = 0

What are the solutions to the equation 3(x-1)^2-14=-2 ?
The solutions to the equation 3(x-1)^2-14=-2 are x=3,x=-1
Find the zeros of 3(x-1)^2-14=-2
The zeros of 3(x-1)^2-14=-2 are x=3,x=-1