What is factor (2^{3+n})/(2^{n+4)} ?

The solution to factor (2^{3+n})/(2^{n+4)} is 1/2

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factor (2^{3+n})/(2^{n+4)}

factor

\frac{2 ^{3 + n}}{2 ^{n + 4}}

\frac{1}{2}

Decimal Notation

0.5

Solution steps

\frac{2 ^{3 + n}}{2 ^{n + 4}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{2 ^{n + 3}}{2 ^{n + 4}} = \frac{1}{2 ^{n + 4 - (n + 3)}}

= \frac{1}{2 ^{n + 4 - (n + 3)}}

Add similar elements:

n + 4 - (n + 3) = 1

= \frac{1}{2}

- 3 cos (2 (t) - 6) + 4

x x^{2} - 24 x + 20

3^{2 n + 2} - 9

(x)^{4} - 2 (x)^{2} + 3

\frac{- 1 - 9 i}{- 2 - 9 i}

What is factor (2^{3+n})/(2^{n+4)} ?
The solution to factor (2^{3+n})/(2^{n+4)} is 1/2