What is factor t^2+1/5 t+5t+1 ?

The solution to factor t^2+1/5 t+5t+1 is (t+1/5)(t+5)

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factor t^2+1/5 t+5t+1

factor

t^{2} + \frac{1}{5} t + 5 t + 1

(t + \frac{1}{5}) (t + 5)

Solution steps

t^{2} + \frac{1}{5} t + 5 t + 1

Add similar elements:

\frac{1}{5} t + 5 t = \frac{26}{5} t

= t^{2} + \frac{26}{5} t + 1

Multiply

\frac{26}{5} t : \frac{26 t}{5}

= t^{2} + \frac{26 t}{5} + 1

Solve

t^{2} + \frac{26 t}{5} + 1 = 0 : t = - \frac{1}{5}, t = - 5

Polynom can therefore be factored into

= (t - (- \frac{1}{5})) (t - (- 5))

Refine

= (t + 5) (t + \frac{1}{5})

x^{(2)} - 3 x + 4

50 (x^{''})

(x - x) (x + 6)

(x^{2} - 14) - (5 x)

[{5 cosh (3 t)}]

What is factor t^2+1/5 t+5t+1 ?
The solution to factor t^2+1/5 t+5t+1 is (t+1/5)(t+5)