What is factor cos(atctan(4)-arctan(3)) ?

The solution to factor cos(atctan(4)-arctan(3)) is cos(4a^2nt^2c-arctan(3))

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factor cos(atctan(4)-arctan(3))

factor

cos (a t c t an (4) - arctan (3))

cos (4 a^{2} n t^{2} c - arctan (3))

Solution steps

cos (a t c t an (4) - arctan (3))

Remove parentheses:

(a) = a

= cos (a t c t an \cdot 4 - arctan (3))

a t c t an \cdot 4 = 4 a^{2} n t^{2} c

= cos (4 a^{2} n t^{2} c - arctan (3))

\frac{4}{3} π (2 \cdot 2)^{3}

\frac{( 2 ^{1 0^{12} - 8} )}{390625}

x^{2 - 4 x - 21}

x^{2} + \frac{1}{2} x + 1

sin^{2} (x) (cos (x))^{2}

What is factor cos(atctan(4)-arctan(3)) ?
The solution to factor cos(atctan(4)-arctan(3)) is cos(4a^2nt^2c-arctan(3))