What is factor ab+b^2-ac-bc ?

The solution to factor ab+b^2-ac-bc is (b-c)(a+b)

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factor ab+b^2-ac-bc

factor

ab + b^{2} - a c - b c

(b - c) (a + b)

Solution steps

ab + b^{2} - a c - b c

Factor out common term

a

= a (b - c) + b^{2} - b c

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

b^{2} = bb

= a (b - c) + bb - b c

Factor out common term

b

= a (b - c) + b (b - c)

Factor out common term

(b - c)

= (b - c) (a + b)

- 2 A + (- 1.5) B + C + 1.5 D

4 (\frac{1}{2})^{2}

e^{4 t} sin (h) (5 t)

\frac{d}{d c} ((t) (c e^{r (t, c) t}))

d t (- t)