What is the d/(d{x)}(({f}(x,y))e^{({x}+{y})}) ?

The d/(d{x)}(({f}(x,y))e^{({x}+{y})}) is {f}(x,y)e^{{x}+{y}}(1+d/(d{x)}({y}))

What is the first d/(d{x)}(({f}(x,y))e^{({x}+{y})}) ?

The first d/(d{x)}(({f}(x,y))e^{({x}+{y})}) is {f}(x,y)e^{{x}+{y}}(1+d/(d{x)}({y}))

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\frac{d}{d x} ((f (x, y)) e^{(x + y)})

f (x, y) e^{x + y} (1 + \frac{d}{d x} (y))

Solution steps

\frac{d}{d x} ((f (x, y)) e^{(x + y)})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= f (x, y) \frac{d}{d x} (e^{x + y})

Apply the chain rule:

e^{x + y} \frac{d}{d x} (x + y)

= e^{x + y} \frac{d}{d x} (x + y)

\frac{d}{d x} (x + y) = 1 + \frac{d}{d x} (y)

= f (x, y) e^{x + y} (1 + \frac{d}{d x} (y))

a - b^{9}

25 m^{2 + 10}

(- \frac{7 π}{9}) - π

e^{- 4 x} - 4 x e^{- 4 x}

z^{3} + (y^{2} - 4 x)

What is the d/(d{x)}(({f}(x,y))e^{({x}+{y})}) ?
The d/(d{x)}(({f}(x,y))e^{({x}+{y})}) is {f}(x,y)e^{{x}+{y}}(1+d/(d{x)}({y}))
What is the first d/(d{x)}(({f}(x,y))e^{({x}+{y})}) ?
The first d/(d{x)}(({f}(x,y))e^{({x}+{y})}) is {f}(x,y)e^{{x}+{y}}(1+d/(d{x)}({y}))