What are the solutions to the equation x^2+20x+100=36 ?

The solutions to the equation x^2+20x+100=36 are x=-4,x=-16

Find the zeros of x^2+20x+100=36

The zeros of x^2+20x+100=36 are x=-4,x=-16

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x^{2} + 20 x + 100 = 36

x = - 4, x = - 16

Solution steps

x^{2} + 20 x + 100 = 36

Move

36

to the left side

x^{2} + 20 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 64}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot 64 = 12

x_{1, 2} = \frac{- 20 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 12}{2 \cdot 1}, x_{2} = \frac{- 20 - 12}{2 \cdot 1}

x = \frac{- 20 + 12}{2 \cdot 1} : - 4

x = \frac{- 20 - 12}{2 \cdot 1} : - 16

The solutions to the quadratic equation are:

x = - 4, x = - 16

- 3 x^{2} - 3 x + 6

\frac{x + 1}{x + 2} \geq 2

\frac{14}{x + 7} \leq 2

\frac{x + 6}{6 - x} < 0

\frac{45}{9}

What are the solutions to the equation x^2+20x+100=36 ?
The solutions to the equation x^2+20x+100=36 are x=-4,x=-16
Find the zeros of x^2+20x+100=36
The zeros of x^2+20x+100=36 are x=-4,x=-16