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Popular >

factor 4Δ^2+20Δ+25

Solution

factor

4 Δ^{2} + 20Δ + 25

Solution

(2Δ + 5)^{2}

Solution steps

4 Δ^{2} + 20Δ + 25

Rewrite

4 Δ^{2} + 20Δ + 25

as

(2Δ)^{2} + 2 \cdot 2Δ \cdot 5 + 5^{2}

= (2Δ)^{2} + 2 \cdot 2Δ \cdot 5 + 5^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = 2Δ, b = 5

= (2Δ + 5)^{2}

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Frequently Asked Questions (FAQ)

What is factor 4Δ^2+20Δ+25 ?
The solution to factor 4Δ^2+20Δ+25 is (2Δ+5)^2