What is factor (2x-5)+4x^2 ?

The solution to factor (2x-5)+4x^2 is 4(x-(-1+sqrt(21))/4)(x-(-1-sqrt(21))/4)

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factor (2x-5)+4x^2

factor

(2 x - 5) + 4 x^{2}

4 (x - \frac{- 1 + 21}{4}) (x - \frac{- 1 - 21}{4})

Solution steps

(2 x - 5) + 4 x^{2}

Remove parentheses:

(a) = a

= 2 x - 5 + 4 x^{2}

Rewrite as

= 4 (x^{2} + \frac{x}{2} - \frac{5}{4})

Factor

x^{2} + \frac{x}{2} - \frac{5}{4} : (x - \frac{21 - 1}{4}) (x - \frac{- 1 - 21}{4})

4 (x - \frac{21 - 1}{4}) (x - \frac{- 1 - 21}{4})

9 x^{2 - 18 x + 3}

π r + 2 r

21 6^{6} - 27 x^{6}

2 mn - 4 p n + m q - 2 pq

5 - 19 a + 12 a

What is factor (2x-5)+4x^2 ?
The solution to factor (2x-5)+4x^2 is 4(x-(-1+sqrt(21))/4)(x-(-1-sqrt(21))/4)