What are the solutions to the equation 5x^2-2x+9=0 ?

The solutions to the equation 5x^2-2x+9=0 are x= 1/5+i(2sqrt(11))/5 ,x= 1/5-i(2sqrt(11))/5

Find the zeros of 5x^2-2x+9=0

The zeros of 5x^2-2x+9=0 are x= 1/5+i(2sqrt(11))/5 ,x= 1/5-i(2sqrt(11))/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} - 2 x + 9 = 0

x = \frac{1}{5} + i \frac{2 11}{5}, x = \frac{1}{5} - i \frac{2 11}{5}

Solution steps

5 x^{2} - 2 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 5 \cdot 9}{2 \cdot 5}

Simplify

(- 2)^{2} - 4 \cdot 5 \cdot 9 : 411 i

x_{1, 2} = \frac{- ( - 2 ) \pm 4 11 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 11 i}{2 \cdot 5}, x_{2} = \frac{- ( - 2 ) - 4 11 i}{2 \cdot 5}

x = \frac{- ( - 2 ) + 4 11 i}{2 \cdot 5} : \frac{1}{5} + i \frac{2 11}{5}

x = \frac{- ( - 2 ) - 4 11 i}{2 \cdot 5} : \frac{1}{5} - i \frac{2 11}{5}

The solutions to the quadratic equation are:

x = \frac{1}{5} + i \frac{2 11}{5}, x = \frac{1}{5} - i \frac{2 11}{5}

10 x^{2} - 13 x - 3

\frac{1}{3} + \frac{2}{3} - \frac{1}{6}

(10 n)^{\frac{3}{5}}

2^{x} < 8

2 (1)

What are the solutions to the equation 5x^2-2x+9=0 ?
The solutions to the equation 5x^2-2x+9=0 are x= 1/5+i(2sqrt(11))/5 ,x= 1/5-i(2sqrt(11))/5
Find the zeros of 5x^2-2x+9=0
The zeros of 5x^2-2x+9=0 are x= 1/5+i(2sqrt(11))/5 ,x= 1/5-i(2sqrt(11))/5