What is the derivative of x^2y+2x ?

The derivative of x^2y+2x is 2xy+(dy)/(dx)x^2+2

What is the first derivative of x^2y+2x ?

The first derivative of x^2y+2x is 2xy+(dy)/(dx)x^2+2

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\frac{d}{d x} (x^{2} y + 2 x)

2 x y + \frac{d y}{d x} x^{2} + 2

Solution steps

\frac{d}{d x} (x^{2} y + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2} y) + \frac{d}{d x} (2 x)

\frac{d}{d x} (x^{2} y) = 2 x y + \frac{d y}{d x} x^{2}

\frac{d}{d x} (2 x) = 2

= 2 x y + \frac{d y}{d x} x^{2} + 2

x e^{(y - x^{2})}

3 (x z)

e^{(e^{x} + C)}

f (- π)

(3 x)^{3} + (4 y)^{3}

What is the derivative of x^2y+2x ?
The derivative of x^2y+2x is 2xy+(dy)/(dx)x^2+2
What is the first derivative of x^2y+2x ?
The first derivative of x^2y+2x is 2xy+(dy)/(dx)x^2+2