What is factor 10x^8+y^{4n+4x} ?

The solution to factor 10x^8+y^{4n+4x} is 10x^8+y^{4(n+x)}

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factor 10x^8+y^{4n+4x}

factor

10 x^{8} + y^{4 n + 4 x}

10 x^{8} + y^{4 (n + x)}

Solution steps

10 x^{8} + y^{4 n + 4 x}

Factor

4 n + 4 x : 4 (n + x)

= 10 x^{8} + y^{4 (x + n)}

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- cos (6 α + 8 θ) sin (6 α + 8 θ)

\frac{d}{d q} ((w) (836))

What is factor 10x^8+y^{4n+4x} ?
The solution to factor 10x^8+y^{4n+4x} is 10x^8+y^{4(n+x)}