What is factor x^2+1x-10 ?

The solution to factor x^2+1x-10 is (x-(-1+sqrt(41))/2)(x-(-1-sqrt(41))/2)

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factor x^2+1x-10

factor

x^{2} + 1 x - 10

(x - \frac{- 1 + 41}{2}) (x - \frac{- 1 - 41}{2})

Solution steps

x^{2} + 1 \cdot x - 10

Solve

x^{2} + x - 10 = 0 : x = \frac{- 1 + 41}{2}, x = \frac{- 1 - 41}{2}

Polynom can therefore be factored into

= (x - (\frac{- 1 + 41}{2})) (x - (\frac{- 1 - 41}{2}))

Refine

= (x - \frac{41 - 1}{2}) (x - \frac{- 1 - 41}{2})

x 2 - x + 1

x 2 - x + 2

(2.4) - (0.6) v

(x + h) - 1

x^{c + 2} - 14 x^{c + 1} + 24 x^{c}

What is factor x^2+1x-10 ?
The solution to factor x^2+1x-10 is (x-(-1+sqrt(41))/2)(x-(-1-sqrt(41))/2)