What is the d/(ds)((θ)(tan(θ))) ?

The d/(ds)((θ)(tan(θ))) is tan(s)+ssec^2(s)

What is the first d/(ds)((θ)(tan(θ))) ?

The first d/(ds)((θ)(tan(θ))) is tan(s)+ssec^2(s)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d s} ((s) (tan (s)))

tan (s) + s sec^{2} (s)

Solution steps

\frac{d}{d s} ((s) (tan (s)))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = s, g = tan (s)

= \frac{d s}{d s} tan (s) + \frac{d}{d s} (tan (s)) s

\frac{d s}{d s} = 1

\frac{d}{d s} (tan (s)) = sec^{2} (s)

= 1 \cdot tan (s) + sec^{2} (s) s

Simplify

= tan (s) + s sec^{2} (s)

m^{2} + mn + m p + n p

3 V^{5} + V^{125}

\frac{15 - 3 33}{2}

2 a c + 6 b c + 5 a + 15 b

f (x) e^{x - 4}

What is the d/(ds)((θ)(tan(θ))) ?
The d/(ds)((θ)(tan(θ))) is tan(s)+ssec^2(s)
What is the first d/(ds)((θ)(tan(θ))) ?
The first d/(ds)((θ)(tan(θ))) is tan(s)+ssec^2(s)