What is factor cos^6(θ)+sin^6(x) ?

The solution to factor cos^6(θ)+sin^6(x) is (cos^2(θ)+sin^2(x))(cos^4(θ)-cos^2(θ)sin^2(x)+sin^4(x))

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factor cos^6(θ)+sin^6(x)

factor

cos^{6} (θ) + sin^{6} (x)

(cos^{2} (θ) + sin^{2} (x)) (cos^{4} (θ) - cos^{2} (θ) sin^{2} (x) + sin^{4} (x))

Solution steps

cos^{6} (θ) + sin^{6} (x)

Rewrite

cos^{6} (θ) + sin^{6} (x)

(cos^{2} (θ))^{3} + (sin^{2} (x))^{3}

= (cos^{2} (θ))^{3} + (sin^{2} (x))^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(cos^{2} (θ))^{3} + (sin^{2} (x))^{3} = (cos^{2} (θ) + sin^{2} (x)) (cos^{4} (θ) - sin^{2} (x) cos^{2} (θ) + sin^{4} (x))

= (sin^{2} (x) + cos^{2} (θ)) (sin^{4} (x) - sin^{2} (x) cos^{2} (θ) + cos^{4} (θ))

\frac{d}{d t} ((P (t)) (k P (t) (1200 - P (t))))

b^{4} (a^{3} b)

\frac{6 - x}{x ^{2} - 36}

2 x^{'} 1

d [^{'}]

What is factor cos^6(θ)+sin^6(x) ?
The solution to factor cos^6(θ)+sin^6(x) is (cos^2(θ)+sin^2(x))(cos^4(θ)-cos^2(θ)sin^2(x)+sin^4(x))