What are the solutions to the equation x^2-18x+71=0 ?

The solutions to the equation x^2-18x+71=0 are x=9+sqrt(10),x=9-sqrt(10)

Find the zeros of x^2-18x+71=0

The zeros of x^2-18x+71=0 are x=9+sqrt(10),x=9-sqrt(10)

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x^{2} - 18 x + 71 = 0

x = 9 + 10, x = 9 - 10

Solution steps

x^{2} - 18 x + 71 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 71}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 71 = 210

x_{1, 2} = \frac{- ( - 18 ) \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 2 10}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 2 10}{2 \cdot 1}

x = \frac{- ( - 18 ) + 2 10}{2 \cdot 1} : 9 + 10

x = \frac{- ( - 18 ) - 2 10}{2 \cdot 1} : 9 - 10

The solutions to the quadratic equation are:

x = 9 + 10, x = 9 - 10

- 1.2 (8)^{2} + 9.6 (8)

2 < x < 5

6 (3 x - 2) - 5 (2 x + 1) = 4 x - 14

\frac{a ^{2} + 9 a + 18}{a ^{2} + 3 a - 18}

(5^{- 2})^{2}

What are the solutions to the equation x^2-18x+71=0 ?
The solutions to the equation x^2-18x+71=0 are x=9+sqrt(10),x=9-sqrt(10)
Find the zeros of x^2-18x+71=0
The zeros of x^2-18x+71=0 are x=9+sqrt(10),x=9-sqrt(10)