What is factor (n+1)!-1+(n+1)(n+1)! ?

The solution to factor (n+1)!-1+(n+1)(n+1)! is n(n+1)!+2(n+1)!-1

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factor (n+1)!-1+(n+1)(n+1)!

factor

(n + 1)! - 1 + (n + 1) (n + 1)!

n (n + 1)! + 2 (n + 1)! - 1

Solution steps

(n + 1)! - 1 + (n + 1) (n + 1)!

= (n + 1)! - 1 + (n + 1)! (n + 1)

Expand

(n + 1)! (n + 1) : n (n + 1)! + (n + 1)!

= (n + 1)! - 1 + n (n + 1)! + (n + 1)!

Simplify

(n + 1)! - 1 + n (n + 1)! + (n + 1)! : n (n + 1)! + 2 (n + 1)! - 1

= n (n + 1)! + 2 (n + 1)! - 1

[- 100]

911.25 x^{2} + 8.775 x + 0.021125

2 a x + a y - 4 b x - 2 b y

ln (y) (ln (x))

y^{2} e^{2 x} + 2 e^{2 x} y

What is factor (n+1)!-1+(n+1)(n+1)! ?
The solution to factor (n+1)!-1+(n+1)(n+1)! is n(n+1)!+2(n+1)!-1