What are the solutions to the equation x^2=2x-1 ?

The solutions to the equation x^2=2x-1 are x=1

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x^2=2x-1

x^{2} = 2 x - 1

x = 1

Solution steps

x^{2} = 2 x - 1

Move

1

to the left side

x^{2} + 1 = 2 x

Move

2 x

to the left side

x^{2} + 1 - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 2 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 2 )}{2 \cdot 1}

\frac{- ( - 2 )}{2 \cdot 1} = 1

x = 1

The solution to the quadratic equation is:

x = 1

\frac{3 ^{6}}{3 ^{6}}

9 x - 3 = 3 x + 6 x + 2 + 3

(\frac{- 27}{8})^{\frac{4}{3}}

\frac{5 x + 4}{7} = \frac{- 3 x + 12}{3}

- 2 (t + 8) = 12

What are the solutions to the equation x^2=2x-1 ?
The solutions to the equation x^2=2x-1 are x=1
Find the zeros of x^2=2x-1
The zeros of x^2=2x-1 are x=1