What is factor (160+78i)^{0.5} ?

The solution to factor (160+78i)^{0.5} is (2(80+39i))^{1/2}

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factor (160+78i)^{0.5}

factor

(160 + 78 i)^{0.5}

(2 (80 + 39 i))^{\frac{1}{2}}

Solution steps

(160 + 78 i)^{\frac{1}{2}}

Factor

160 + 78 i : 2 (80 + 39 i)

= (2 (80 + 39 i))^{\frac{1}{2}}

p^{2} - \frac{1}{4} i z a r

C (87.14)

a x + a z + b x + b z

(b + (b - 2 x)) (b - (b - 2 x))

32 (x + 1)^{5} - 243 y^{10}

What is factor (160+78i)^{0.5} ?
The solution to factor (160+78i)^{0.5} is (2(80+39i))^{1/2}