What are the solutions to the equation 2x^2+5x-18=0 ?

The solutions to the equation 2x^2+5x-18=0 are x=2,x=-9/2

Find the zeros of 2x^2+5x-18=0

The zeros of 2x^2+5x-18=0 are x=2,x=-9/2

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2 x^{2} + 5 x - 18 = 0

x = 2, x = - \frac{9}{2}

Decimal Notation

x = 2, x = - 4.5

Solution steps

2 x^{2} + 5 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 18 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 18) = 13

x_{1, 2} = \frac{- 5 \pm 13}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 13}{2 \cdot 2}, x_{2} = \frac{- 5 - 13}{2 \cdot 2}

x = \frac{- 5 + 13}{2 \cdot 2} : 2

x = \frac{- 5 - 13}{2 \cdot 2} : - \frac{9}{2}

The solutions to the quadratic equation are:

x = 2, x = - \frac{9}{2}

\frac{3}{5} \geq \frac{2}{5}

\frac{1}{4} (16 x - 12 y + 4 z)

h^{3} - 1

\frac{1}{2} \cdot 8

- 1.2 b - 5.3 \geq 1.9

What are the solutions to the equation 2x^2+5x-18=0 ?
The solutions to the equation 2x^2+5x-18=0 are x=2,x=-9/2
Find the zeros of 2x^2+5x-18=0
The zeros of 2x^2+5x-18=0 are x=2,x=-9/2