What are the solutions to the equation -x^2+4x-4=0 ?

The solutions to the equation -x^2+4x-4=0 are x=2

Find the zeros of -x^2+4x-4=0

The zeros of -x^2+4x-4=0 are x=2

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- x^{2} + 4 x - 4 = 0

x = 2

Solution steps

- x^{2} + 4 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) ( - 4 )}{2 ( - 1 )}

4^{2} - 4 (- 1) (- 4) = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 ( - 1 )}

x = \frac{- 4}{2 ( - 1 )}

\frac{- 4}{2 ( - 1 )} = 2

x = 2

The solution to the quadratic equation is:

x = 2

- 3 (v + 4) = 2 v - 37

\frac{1}{3} \cdot \frac{1}{4}

\frac{1}{2} - \frac{2}{3}

- 6 u + 10 = - 8

\frac{4 ^{- 3}}{2 ^{- 8}}

What are the solutions to the equation -x^2+4x-4=0 ?
The solutions to the equation -x^2+4x-4=0 are x=2
Find the zeros of -x^2+4x-4=0
The zeros of -x^2+4x-4=0 are x=2