What is the first d/(dy)((x)(2x)) ?

The first d/(dy)((x)(2x)) is 4y

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d/(dy)((x)(2x))

\frac{d}{d y} ((y) (2 y))

4 y

Solution steps

\frac{d}{d y} ((y) (2 y))

Simplify

(y) (2 y) : 2 y^{2}

= \frac{d}{d y} (2 y^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 2 y^{2 - 1}

Simplify

= 4 y

5 x^{2} + x^{2}

(Δ^{3}) 2

(9 x^{5} y) + (3 x + 2 y - 7)

x^{8} - 10 x^{4} + 24

5 a^{(2)} - 7