What is the answer to roots 2x+3a+4b ?

The answer to roots 2x+3a+4b is x=(-3a-4b)/2

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roots 2x+3a+4b

roots

2 x + 3 a + 4 b

x = \frac{- 3 a - 4 b}{2}

Solution steps

2 x + 3 a + 4 b

The roots are the intercepts with the x-axis

(y = 0)

2 x + 3 a + 4 b = 0

Move

3 a

to the right side

2 x + 4 b = - 3 a

Move

4 b

to the right side

2 x = - 3 a - 4 b

Divide both sides by

2

x = \frac{- 3 a - 4 b}{2}

f (q) = 3 q - 2

[(6 a + 1) + 3 b]

\frac{3 u}{3 uv - 12 u w}

\frac{x ^{2} - x - 12}{x + 3}

\frac{x ^{2} - x - 12}{x + 7}

What is the answer to roots 2x+3a+4b ?
The answer to roots 2x+3a+4b is x=(-3a-4b)/2