What are the solutions to the equation -3x^2-16=-3x ?

The solutions to the equation -3x^2-16=-3x are x= 1/2-i(sqrt(183))/6 ,x= 1/2+i(sqrt(183))/6

Find the zeros of -3x^2-16=-3x

The zeros of -3x^2-16=-3x are x= 1/2-i(sqrt(183))/6 ,x= 1/2+i(sqrt(183))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 x^{2} - 16 = - 3 x

x = \frac{1}{2} - i \frac{183}{6}, x = \frac{1}{2} + i \frac{183}{6}

Solution steps

- 3 x^{2} - 16 = - 3 x

Move

3 x

to the left side

- 3 x^{2} - 16 + 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 x^{2} + 3 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 3 ) ( - 16 )}{2 ( - 3 )}

Simplify

3^{2} - 4 (- 3) (- 16) : 183 i

x_{1, 2} = \frac{- 3 \pm 183 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 3 + 183 i}{2 ( - 3 )}, x_{2} = \frac{- 3 - 183 i}{2 ( - 3 )}

x = \frac{- 3 + 183 i}{2 ( - 3 )} : \frac{1}{2} - i \frac{183}{6}

x = \frac{- 3 - 183 i}{2 ( - 3 )} : \frac{1}{2} + i \frac{183}{6}

The solutions to the quadratic equation are:

x = \frac{1}{2} - i \frac{183}{6}, x = \frac{1}{2} + i \frac{183}{6}

(\frac{5}{4})^{\frac{3}{2}}

747 \leq - 57 - d

400 = 500 (1 - r)^{2}

4 x^{2} + x + 4 = 0

\frac{5}{x} < 3

What are the solutions to the equation -3x^2-16=-3x ?
The solutions to the equation -3x^2-16=-3x are x= 1/2-i(sqrt(183))/6 ,x= 1/2+i(sqrt(183))/6
Find the zeros of -3x^2-16=-3x
The zeros of -3x^2-16=-3x are x= 1/2-i(sqrt(183))/6 ,x= 1/2+i(sqrt(183))/6