What is (x+5)(x^2-9)(1-x)>0 ?

The solution to (x+5)(x^2-9)(1-x)>0 is -5<x<-3\lor 1<x<3

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(x+5)(x^2-9)(1-x)>0

(x + 5) (x^{2} - 9) (1 - x) > 0

- 5 < x < - 3 or 1 < x < 3

Interval Notation

(- 5, - 3) \cup (1, 3)

Solution steps

(x + 5) (x^{2} - 9) (1 - x) > 0

Factor

(x + 5) (x^{2} - 9) (1 - x) : - (x + 5) (x + 3) (x - 3) (x - 1)

- (x + 5) (x + 3) (x - 3) (x - 1) > 0

Multiply both sides by

- 1

(reverse the inequality)

(- (x + 5) (x + 3) (x - 3) (x - 1)) (- 1) < 0 \cdot (- 1)

Simplify

(x + 5) (x + 3) (x - 3) (x - 1) < 0

Identify the intervals

- 5 < x < - 3 or 1 < x < 3

\frac{x + 2}{x - 3} < 2

57 = 12 - 5 v

x^{4} + 2 x^{2} + 1

8 - 2 (z - 6) = 3 (- 3 z + 7) + 8

2 m p + 15 + 3 p + 10 m

What is (x+5)(x^2-9)(1-x)>0 ?
The solution to (x+5)(x^2-9)(1-x)>0 is -5<x<-3\lor 1<x<3