What is factor x^2-(20x+4)/(25) ?

The solution to factor x^2-(20x+4)/(25) is x^2-(4(5x+1))/(25)

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factor x^2-(20x+4)/(25)

factor

x^{2} - \frac{20 x + 4}{25}

x^{2} - \frac{4 ( 5 x + 1 )}{25}

Solution steps

x^{2} - \frac{20 x + 4}{25}

Factor

20 x + 4 : 4 (5 x + 1)

= x^{2} - \frac{4 ( 5 x + 1 )}{25}

1 2^{2} - x - 6

a^{36} - a^{12.25}

(2^{x})^{2} - 2^{x} - 2

4 t^{3} + 100 \cdot π - 60 t^{2}

(10 b^{2}) - (x^{2})

What is factor x^2-(20x+4)/(25) ?
The solution to factor x^2-(20x+4)/(25) is x^2-(4(5x+1))/(25)