What are the solutions to the equation x^2-8x+2=0 ?

The solutions to the equation x^2-8x+2=0 are x=4+sqrt(14),x=4-sqrt(14)

Find the zeros of x^2-8x+2=0

The zeros of x^2-8x+2=0 are x=4+sqrt(14),x=4-sqrt(14)

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x^{2} - 8 x + 2 = 0

x = 4 + 14, x = 4 - 14

Solution steps

x^{2} - 8 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 2 = 214

x_{1, 2} = \frac{- ( - 8 ) \pm 2 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 14}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 14}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 14}{2 \cdot 1} : 4 + 14

x = \frac{- ( - 8 ) - 2 14}{2 \cdot 1} : 4 - 14

The solutions to the quadratic equation are:

x = 4 + 14, x = 4 - 14

49 r^{3} + 42 r^{2} - 42 r - 36

12 x y - 9 x - 8 y + 6

5 x - 2 = 2 x + 13

3 r^{5} s \cdot 10 s^{3}

(x + 2) (x + 3) + 3 (x + 2) \leq 0

What are the solutions to the equation x^2-8x+2=0 ?
The solutions to the equation x^2-8x+2=0 are x=4+sqrt(14),x=4-sqrt(14)
Find the zeros of x^2-8x+2=0
The zeros of x^2-8x+2=0 are x=4+sqrt(14),x=4-sqrt(14)