What is factor (-3a^6b^2)+12a^{18}b^6 ?

The solution to factor (-3a^6b^2)+12a^{18}b^6 is 3a^6b^2(2a^6b^2+1)(2a^6b^2-1)

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factor (-3a^6b^2)+12a^{18}b^6

factor

(- 3 a^{6} b^{2}) + 12 a^{18} b^{6}

3 a^{6} b^{2} (2 a^{6} b^{2} + 1) (2 a^{6} b^{2} - 1)

Solution steps

(- 3 a^{6} b^{2}) + 12 a^{18} b^{6}

Remove parentheses:

(- a) = - a

= - 3 a^{6} b^{2} + 12 a^{18} b^{6}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

a^{18} b^{6} = a^{6} a^{12} b^{2} b^{4}

= - 3 a^{6} b^{2} + 12 a^{6} a^{12} b^{2} b^{4}

Rewrite

12

4 \cdot 3

= - 3 a^{6} b^{2} + 4 \cdot 3 a^{6} a^{4 \cdot 3} b^{2} b^{4}

Factor out common term

3 a^{6} b^{2}

= 3 a^{6} b^{2} (- 1 + 4 a^{12} b^{4})

Factor

4 a^{12} b^{4} - 1 : (2 a^{6} b^{2} + 1) (2 a^{6} b^{2} - 1)

= 3 a^{6} b^{2} (2 a^{6} b^{2} + 1) (2 a^{6} b^{2} - 1)

m^{8} - 49

\frac{d}{d x} ((q (x)) 3) - 2 q (x)

(x^{5} y^{5}) - 1

tan^{2} (θ) - 3 tan (θ) + 2

E (0.4)

What is factor (-3a^6b^2)+12a^{18}b^6 ?
The solution to factor (-3a^6b^2)+12a^{18}b^6 is 3a^6b^2(2a^6b^2+1)(2a^6b^2-1)