What are the solutions to the equation 2x^2+98=0 ?

The solutions to the equation 2x^2+98=0 are x=7i,x=-7i

Find the zeros of 2x^2+98=0

The zeros of 2x^2+98=0 are x=7i,x=-7i

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2 x^{2} + 98 = 0

x = 7 i, x = - 7 i

Solution steps

2 x^{2} + 98 = 0

Move

98

to the right side

2 x^{2} = - 98

Divide both sides by

2

x^{2} = - 49

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 49, x = - - 49

- 49 = 7 i

- - 49 = - 7 i

x = 7 i, x = - 7 i

- 4 = \frac{x}{20} - 5

∣ 3 x - 7 ∣ + 3 < 1

16 z^{2} + 59 = 64 z

x^{2} - 7 x + 12 > 0

\frac{2035}{1728} + \frac{1}{125} + \frac{1}{216} + \frac{1}{343} + \frac{1}{512}

What are the solutions to the equation 2x^2+98=0 ?
The solutions to the equation 2x^2+98=0 are x=7i,x=-7i
Find the zeros of 2x^2+98=0
The zeros of 2x^2+98=0 are x=7i,x=-7i