What is factor je^{jk_{1}z}-je^{jk_{2}z} ?

The solution to factor je^{jk_{1}z}-je^{jk_{2}z} is j(e^{k_{1}jz}-e^{k_{2}jz})

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factor je^{jk_{1}z}-je^{jk_{2}z}

factor

j e^{j k_{1} z} - j e^{j k_{2} z}

j (e^{k_{1} j z} - e^{k_{2} j z})

Solution steps

j e^{j k_{1} z} - j e^{j k_{2} z}

Factor out common term

j

= j (e^{k_{1} j z} - e^{k_{2} j z})

2 π y^{2} - 38 π y + 163 π

2 π r^{3} - 6 π r^{2} h

x^{(3)} - 3 x + 4

343 x^{3} y^{3} - 64 z^{3}

x^{2} - 13 + 30

What is factor je^{jk_{1}z}-je^{jk_{2}z} ?
The solution to factor je^{jk_{1}z}-je^{jk_{2}z} is j(e^{k_{1}jz}-e^{k_{2}jz})