What is the first d/(da)(a^5+b^5) ?

The first d/(da)(a^5+b^5) is 5a^4

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d/(da)(a^5+b^5)

\frac{d}{d a} (a^{5} + b^{5})

5 a^{4}

Solution steps

\frac{d}{d a} (a^{5} + b^{5})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d a} (a^{5}) + \frac{d}{d a} (b^{5})

\frac{d}{d a} (a^{5}) = 5 a^{4}

\frac{d}{d a} (b^{5}) = 0

= 5 a^{4} + 0

Simplify

= 5 a^{4}

- y \cdot y

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(2 a - b)^{3} - (3 b - a)^{3}