What is factor x^2-5+4 ?

The solution to factor x^2-5+4 is (x+1)(x-1)

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factor x^2-5+4

factor

x^{2} - 5 + 4

(x + 1) (x - 1)

Solution steps

x^{2} - 5 + 4

Add/Subtract the numbers:

- 5 + 4 = - 1

= x^{2} - 1

Rewrite

1

1^{2}

= x^{2} - 1^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

x^{2} - 1^{2} = (x + 1) (x - 1)

= (x + 1) (x - 1)

4^{3} - 9 x + 1

5 - (3 (cos (x)))

- 5 x^{8} e^{x} - 5 sin (x) cos (x)

y - 3 (2)^{x} - 2

f (c) = 3 c