What is factor 1+ax^{-1}+bx^{-2} ?

The solution to factor 1+ax^{-1}+bx^{-2} is 1+a/x+b/(x^2)

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factor 1+ax^{-1}+bx^{-2}

factor

1 + a x^{- 1} + b x^{- 2}

1 + \frac{a}{x} + \frac{b}{x ^{2}}

Solution steps

1 + a x^{- 1} + b x^{- 2}

a x^{- 1} = \frac{a}{x}

b x^{- 2} = \frac{b}{x ^{2}}

= 1 + \frac{a}{x} + \frac{b}{x ^{2}}

\frac{d}{d t} (a t^{2} e^{t} + 5 t)

x^{2} - 6 - 6

5 - 2 x + 4 x - 3

\frac{x ^{2} + 6 x - 40}{2}

(X^{2} - 9) + 1

What is factor 1+ax^{-1}+bx^{-2} ?
The solution to factor 1+ax^{-1}+bx^{-2} is 1+a/x+b/(x^2)