What is the d/(d{x)}(({f}(x,y))({x}^2{y})) ?

The d/(d{x)}(({f}(x,y))({x}^2{y})) is {f}(x,y){y}*2{x}^{2-1}

What is the first d/(d{x)}(({f}(x,y))({x}^2{y})) ?

The first d/(d{x)}(({f}(x,y))({x}^2{y})) is {f}(x,y){y}*2{x}^{2-1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} ((f (x, y)) (x^{2} y))

f (x, y) y \cdot 2 x^{2 - 1}

Solution steps

\frac{d}{d x} ((f (x, y)) (x^{2} y))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= f (x, y) y \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= f (x, y) y \cdot 2 x^{2 - 1}

e^{3} - 125

2 i z a r^{5} x^{2} + 24 x - 1485

26 + 8 \cdot 2^{\frac{3}{4}}

\frac{4}{3} x

x^{2} + 49 - 625

What is the d/(d{x)}(({f}(x,y))({x}^2{y})) ?
The d/(d{x)}(({f}(x,y))({x}^2{y})) is {f}(x,y){y}*2{x}^{2-1}
What is the first d/(d{x)}(({f}(x,y))({x}^2{y})) ?
The first d/(d{x)}(({f}(x,y))({x}^2{y})) is {f}(x,y){y}*2{x}^{2-1}