What is factor z^2+(3-i)z-3i ?

The solution to factor z^2+(3-i)z-3i is (z^2+3z)+i(-3-z)

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factor z^2+(3-i)z-3i

factor

z^{2} + (3 - i) z - 3 i

(z^{2} + 3 z) + i (- 3 - z)

Solution steps

z^{2} + (3 - i) z - 3 i

Rewrite

z^{2} + (3 - i) z - 3 i

in standard complex form:

(z^{2} + 3 z) + (- z - 3) i

= (z^{2} + 3 z) + (- z - 3) i

2 e^{10} - 2 e^{2}

A (3.2)

A (3.5)

\frac{27 x ^{3} - 8}{27}

x^{- 1} - 3 x^{- 2} + 2 x^{- 3}

What is factor z^2+(3-i)z-3i ?
The solution to factor z^2+(3-i)z-3i is (z^2+3z)+i(-3-z)