What is factor-(b+c)^2+a^2 ?

The solution to factor-(b+c)^2+a^2 is (a+b+c)(a-b-c)

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factor-(b+c)^2+a^2

factor

- (b + c)^{2} + a^{2}

(a + b + c) (a - b - c)

Solution steps

- (b + c)^{2} + a^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

a^{2} - (b + c)^{2} = (a + (b + c)) (a - (b + c))

= (a + (b + c)) (a - (b + c))

Refine

= (b + c + a) (a - b - c)

+ (x + y)

+ (x - 8)

t^{6 a} - (t^{2 a} - 1)^{3}

(3 + h)^{- 1}

x^{2} - \frac{4}{3} x - 4

What is factor-(b+c)^2+a^2 ?
The solution to factor-(b+c)^2+a^2 is (a+b+c)(a-b-c)