What is the answer to roots (ln(x))^3+C ?

The answer to roots (ln(x))^3+C is x=e^{-\sqrt[3]{C}}

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roots (ln(x))^3+C

roots

(ln (x))^{3} + C

x = e^{- 3 C}

Solution steps

(ln (x))^{3} + C

The roots are the intercepts with the x-axis

(y = 0)

(ln (x))^{3} + C = 0

Rewrite the equation with

ln (x) = u

(u)^{3} + C = 0

Solve

u^{3} + C = 0 : u = 3 - C

u = 3 - C

Substitute back

u = ln (x),

solve for

x

Solve

ln (x) = 3 - C : x = e^{- 3 C}

x = e^{- 3 C}

Verify Solutions:

x = e^{- 3 C}

True

The solution is

x = e^{- 3 C}

(x + 2)^{2} + (y + 5)^{2}

(4 x) (x - 5)

e^{x} + e^{y + x} - e^{2 x}

arctan (9 x^{2} - 1)

\frac{d}{d x} ((3) x^{3}) + 7

What is the answer to roots (ln(x))^3+C ?
The answer to roots (ln(x))^3+C is x=e^{-\sqrt[3]{C}}