What is the derivative of (sin(x+y)^2) ?

The derivative of (sin(x+y)^2) is 2sin(x+y)cos(x+y)(1+(dy)/(dx))

What is the first derivative of (sin(x+y)^2) ?

The first derivative of (sin(x+y)^2) is 2sin(x+y)cos(x+y)(1+(dy)/(dx))

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\frac{d}{d x} ((sin (x + y))^{2})

2 sin (x + y) cos (x + y) (1 + \frac{d y}{d x})

Solution steps

\frac{d}{d x} ((sin (x + y))^{2})

Apply the chain rule:

2 sin (x + y) \frac{d}{d x} (sin (x + y))

= 2 sin (x + y) \frac{d}{d x} (sin (x + y))

\frac{d}{d x} (sin (x + y)) = cos (x + y) (1 + \frac{d y}{d x})

= 2 sin (x + y) cos (x + y) (1 + \frac{d y}{d x})

81 x^{2} + 0 x + 16

2100 + 20 (x) - 0.1 (x)^{2}

125 n^{9} p^{6} - 27 s^{6} f^{3}

(\frac{3 π}{2}) + 2 π

f (x) = sin^{(2)} (x) + 6 x - 2

What is the derivative of (sin(x+y)^2) ?
The derivative of (sin(x+y)^2) is 2sin(x+y)cos(x+y)(1+(dy)/(dx))
What is the first derivative of (sin(x+y)^2) ?
The first derivative of (sin(x+y)^2) is 2sin(x+y)cos(x+y)(1+(dy)/(dx))