What is factor (4x-8)/(x^2-1) ?

The solution to factor (4x-8)/(x^2-1) is (4(x-2))/((x+1)(x-1))

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factor (4x-8)/(x^2-1)

factor

\frac{4 x - 8}{x ^{2} - 1}

\frac{4 ( x - 2 )}{( x + 1 ) ( x - 1 )}

Solution steps

\frac{4 x - 8}{x ^{2} - 1}

Factor

x^{2} - 1 : (x + 1) (x - 1)

= \frac{4 x - 8}{( x + 1 ) ( x - 1 )}

Factor

4 x - 8 : 4 (x - 2)

= \frac{4 ( x - 2 )}{( x + 1 ) ( x - 1 )}

x^{5} + (- x^{2})

1 + e^{2} - 2 e

\frac{3 x + 3}{x}

- x ((- 6 - x) (7 - x) + 42)

2 y^{'} (t) - 4 y

What is factor (4x-8)/(x^2-1) ?
The solution to factor (4x-8)/(x^2-1) is (4(x-2))/((x+1)(x-1))