What is factor 2x^{2-n}+x^{n-1} ?

The solution to factor 2x^{2-n}+x^{n-1} is x^{-1-n}(2x^3+x^{2n})

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factor 2x^{2-n}+x^{n-1}

factor

2 x^{2 - n} + x^{n - 1}

x^{- 1 - n} (2 x^{3} + x^{2 n})

Solution steps

2 x^{2 - n} + x^{n - 1}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

= 2 x^{2} x^{- n} + x^{- 1} x^{n}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

x^{2} = x^{- 1} x^{3}, x^{n} = x^{- n} x^{2 n}

= 2 x^{- 1} x^{3} x^{- n} + x^{- n} x^{2 n} x^{- 1}

Factor out common term

x^{- 1} x^{- n}

= x^{- 1} x^{- n} (2 x^{3} + x^{2 n})

Refine

= x^{- n - 1} (2 x^{3} + x^{2 n})

3 P y + (P - 1)

[- 12.5]

2 e^{- j θ^{2}} + 2 e^{j θ^{2}}

(x)^{6}

6 cos^{2} (x) + 5 cos (x) - 6

What is factor 2x^{2-n}+x^{n-1} ?
The solution to factor 2x^{2-n}+x^{n-1} is x^{-1-n}(2x^3+x^{2n})