What is the derivative of 7e^x-7e^{x+h} ?

The derivative of 7e^x-7e^{x+h} is 7e^x-7e^{x+h}

What is the first derivative of 7e^x-7e^{x+h} ?

The first derivative of 7e^x-7e^{x+h} is 7e^x-7e^{x+h}

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\frac{d}{d x} (7 e^{x} - 7 e^{x + h})

7 e^{x} - 7 e^{x + h}

Solution steps

\frac{d}{d x} (7 e^{x} - 7 e^{x + h})

Treat

h

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (7 e^{x}) - \frac{d}{d x} (7 e^{x + h})

\frac{d}{d x} (7 e^{x}) = 7 e^{x}

\frac{d}{d x} (7 e^{x + h}) = 7 e^{x + h}

= 7 e^{x} - 7 e^{x + h}

φ (1.0053)

(2 y^{2}) d y

2 x y - a x + x^{2} - 2 a y

(6 d x^{2}) - (6 x)

12 5^{3} - 5^{2} + x + 3

What is the derivative of 7e^x-7e^{x+h} ?
The derivative of 7e^x-7e^{x+h} is 7e^x-7e^{x+h}
What is the first derivative of 7e^x-7e^{x+h} ?
The first derivative of 7e^x-7e^{x+h} is 7e^x-7e^{x+h}