What is factor (x^2-4+5x)/1 ?

The solution to factor (x^2-4+5x)/1 is (x-(-5+sqrt(41))/2)(x-(-5-sqrt(41))/2)

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factor (x^2-4+5x)/1

factor

\frac{x ^{2} - 4 + 5 x}{1}

(x - \frac{- 5 + 41}{2}) (x - \frac{- 5 - 41}{2})

Solution steps

\frac{x ^{2} - 4 + 5 x}{1}

Apply rule

\frac{a}{1} = a

= x^{2} - 4 + 5 x

Solve

x^{2} + 5 x - 4 = 0 : x = \frac{- 5 + 41}{2}, x = \frac{- 5 - 41}{2}

Polynom can therefore be factored into

= (x - (\frac{- 5 + 41}{2})) (x - (\frac{- 5 - 41}{2}))

Refine

= (x - \frac{41 - 5}{2}) (x - \frac{- 5 - 41}{2})

8 a^{5 b^{2 c^{64} + 2 a^{3 + 4 b - 6 c}}}

- 1 (x + 6)^{2} + 1

(2 x) + (4 y)

x + (- 3 y)

e^{I n (7)}

What is factor (x^2-4+5x)/1 ?
The solution to factor (x^2-4+5x)/1 is (x-(-5+sqrt(41))/2)(x-(-5-sqrt(41))/2)