What is factor 2x^2-9-6x-3x-18 ?

The solution to factor 2x^2-9-6x-3x-18 is 2(x-(3(sqrt(33)+3))/4)(x+(3(sqrt(33)-3))/4)

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factor 2x^2-9-6x-3x-18

factor

2 x^{2} - 9 - 6 x - 3 x - 18

2 (x - \frac{3 ( 33 + 3 )}{4}) (x + \frac{3 ( 33 - 3 )}{4})

Solution steps

2 x^{2} - 9 - 6 x - 3 x - 18

Add similar elements:

- 6 x - 3 x = - 9 x

= 2 x^{2} - 9 - 9 x - 18

Group like terms

= 2 x^{2} - 9 x - 9 - 18

Subtract the numbers:

- 9 - 18 = - 27

= 2 x^{2} - 9 x - 27

Rewrite as

= 2 (x^{2} - \frac{9 x}{2} - \frac{27}{2})

Factor

x^{2} - \frac{9 x}{2} - \frac{27}{2} : (x - \frac{9 + 3 33}{4}) (x - \frac{9 - 3 33}{4})

2 (x - \frac{9 + 3 33}{4}) (x - \frac{9 - 3 33}{4})

Factor

9 + 333 : 3 (33 + 3)

= 2 (x - \frac{3 ( 3 + 33 )}{4}) (x - \frac{9 - 3 33}{4})

Factor

9 - 333 : - 3 (33 - 3)

= 2 (x - \frac{3 ( 3 + 33 )}{4}) (x - \frac{- 3 ( 33 - 3 )}{4})

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= 2 (x - \frac{3 ( 3 + 33 )}{4}) (x - (- \frac{3 ( 33 - 3 )}{4}))

Apply rule

- (- a) = a

= 2 (x - \frac{3 ( 33 + 3 )}{4}) (x + \frac{3 ( 33 - 3 )}{4})

x + (- 10)

2 cos^{2} (- cos (- 1))

(\infty) - e^{- \infty}

e^{a t} sin (b t) + e^{a t} cos (b t)

sin (5 x - 5 y)

What is factor 2x^2-9-6x-3x-18 ?
The solution to factor 2x^2-9-6x-3x-18 is 2(x-(3(sqrt(33)+3))/4)(x+(3(sqrt(33)-3))/4)