What are the solutions to the equation (x+2)^2=-4 ?

The solutions to the equation (x+2)^2=-4 are x=2i-2,x=-2i-2

Find the zeros of (x+2)^2=-4

The zeros of (x+2)^2=-4 are x=2i-2,x=-2i-2

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(x + 2)^{2} = - 4

x = 2 i - 2, x = - 2 i - 2

Solution steps

(x + 2)^{2} = - 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = - 4 : x = 2 i - 2

Solve

x + 2 = - - 4 : x = - 2 i - 2

The solutions to the quadratic equation are:

x = 2 i - 2, x = - 2 i - 2

∣ x - 5 ∣ = 0.04

- 9 > k - 2 \geq - 15

x^{2} = - 196

e^{x^{2}} \cdot e^{- x^{2}}

6 b^{2} + 4 b = 130

What are the solutions to the equation (x+2)^2=-4 ?
The solutions to the equation (x+2)^2=-4 are x=2i-2,x=-2i-2
Find the zeros of (x+2)^2=-4
The zeros of (x+2)^2=-4 are x=2i-2,x=-2i-2