What is factor (16x^4-81)/(2x+3) ?

The solution to factor (16x^4-81)/(2x+3) is (4x^2+9)(2x-3)

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factor (16x^4-81)/(2x+3)

factor

\frac{16 x ^{4} - 81}{2 x + 3}

(4 x^{2} + 9) (2 x - 3)

Solution steps

\frac{16 x ^{4} - 81}{2 x + 3}

Factor

16 x^{4} - 81 : (4 x^{2} + 9) (2 x + 3) (2 x - 3)

= \frac{( 4 x ^{2} + 9 ) ( 2 x + 3 ) ( 2 x - 3 )}{2 x + 3}

Cancel the common factor:

2 x + 3

= (4 x^{2} + 9) (2 x - 3)

4 (4^{2})

ln (x^{3} - 2 x^{2} + x)

10 m x + 5 m y - 6 n x - 3 n y

\frac{( 3 a - 1 ) ^{2}}{2}

3 (x + 4 e^{2} - 8)

What is factor (16x^4-81)/(2x+3) ?
The solution to factor (16x^4-81)/(2x+3) is (4x^2+9)(2x-3)