What is expand (x+Δx)^2-4(x+Δx) ?

The solution to expand (x+Δx)^2-4(x+Δx) is x^2+2Δx^2+Δ^2x^2-4x-4Δx

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expand (x+Δx)^2-4(x+Δx)

expand

(x + Δ x)^{2} - 4 (x + Δ x)

x^{2} + 2Δ x^{2} + Δ^{2} x^{2} - 4 x - 4Δ x

Solution steps

(x + Δ x)^{2} - 4 (x + Δ x)

Expand

- 4 (x + Δ x) : - 4 x - 4Δ x

= (x + Δ x)^{2} - 4 x - 4Δ x

(x + Δ x)^{2} : x^{2} + 2Δ x^{2} + Δ^{2} x^{2}

= x^{2} + 2Δ x^{2} + Δ^{2} x^{2} - 4 x - 4Δ x

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(2 e^{3 x} + e^{- 3 x})^{2}

What is expand (x+Δx)^2-4(x+Δx) ?
The solution to expand (x+Δx)^2-4(x+Δx) is x^2+2Δx^2+Δ^2x^2-4x-4Δx