What is expand (x(x-5))/(x^2-9) ?

The solution to expand (x(x-5))/(x^2-9) is (x^2-5x)/(x^2-9)

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expand (x(x-5))/(x^2-9)

expand

\frac{x ( x - 5 )}{x ^{2} - 9}

\frac{x ^{2} - 5 x}{x ^{2} - 9}

Solution steps

\frac{x ( x - 5 )}{x ^{2} - 9}

Expand

x (x - 5) : x^{2} - 5 x

= \frac{x ^{2} - 5 x}{x ^{2} - 9}

\frac{8 x + 3}{( x + 2 ) ( x + 3 )}

(- 1, 1) y (5, - \frac{7}{2})

\frac{( x y + 1 ) ^{2}}{x y - 1}

(8 hk + 5 e f) (8 hk - 5 e f)

(\frac{x + 1}{2})^{5}

What is expand (x(x-5))/(x^2-9) ?
The solution to expand (x(x-5))/(x^2-9) is (x^2-5x)/(x^2-9)