What is expand ((x-1)(x-3))/3 ?

The solution to expand ((x-1)(x-3))/3 is (x^2)/3-(4x)/3+1

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expand ((x-1)(x-3))/3

expand

\frac{( x - 1 ) ( x - 3 )}{3}

\frac{x ^{2}}{3} - \frac{4 x}{3} + 1

Solution steps

\frac{( x - 1 ) ( x - 3 )}{3}

Expand

(x - 1) (x - 3) : x^{2} - 4 x + 3

= \frac{x ^{2} - 4 x + 3}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} - 4 x + 3}{3} = \frac{x ^{2}}{3} - \frac{4 x}{3} + \frac{3}{3}

= \frac{x ^{2}}{3} - \frac{4 x}{3} + \frac{3}{3}

Apply rule

\frac{a}{a} = 1

\frac{3}{3} = 1

= \frac{x ^{2}}{3} - \frac{4 x}{3} + 1

(5 + 2) 5 - 25

(e + 3)^{2}

(x^{3} + 3 x^{2} + 5)^{5}

\frac{27 \cdot ( s + 2 )}{2}

T (x + 2 y + z, x + 2 z, x + y + 2 z)

What is expand ((x-1)(x-3))/3 ?
The solution to expand ((x-1)(x-3))/3 is (x^2)/3-(4x)/3+1