What is expand (x^2-3x+2)/((x+1)^2) ?

The solution to expand (x^2-3x+2)/((x+1)^2) is (x^2-3x+2)/(x^2+2x+1)

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expand (x^2-3x+2)/((x+1)^2)

expand

\frac{x ^{2} - 3 x + 2}{( x + 1 ) ^{2}}

\frac{x ^{2} - 3 x + 2}{x ^{2} + 2 x + 1}

Solution steps

\frac{x ^{2} - 3 x + 2}{( x + 1 ) ^{2}}

(x + 1)^{2} = x^{2} + 2 x + 1

= \frac{x ^{2} - 3 x + 2}{x ^{2} + 2 x + 1}

(2 x + 3) + (2 y - 2) y^{'} (x)

(x^{2} + 2 x - 5)^{6}

(i + k + j + 2) \cdot (i + ik + kj + j)^{2}

π r^{2} (9.3 - h)

(1 + x - 2 x^{2})^{5}

What is expand (x^2-3x+2)/((x+1)^2) ?
The solution to expand (x^2-3x+2)/((x+1)^2) is (x^2-3x+2)/(x^2+2x+1)